SOLUTION: A tiger and a lion start at exactly the same place on the same road and run in the same direction. if the tiger runs 30 mph and the lion runs at only 2 mph but starts 16 hours befo
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Question 1102263: A tiger and a lion start at exactly the same place on the same road and run in the same direction. if the tiger runs 30 mph and the lion runs at only 2 mph but starts 16 hours before the tiger, how many hours will the tiger have to run before it catches the lion? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39620) (Show Source):
Time to catch = = hours = hours = hours.
Explanations:
2*16 = 32 miles in the numerator is the "head start distance".
(30-2) = 28 miles per hour in the denominator is their relative speed,
which is EXACTLY THE RATE of decreasing the distance between them.
2 - Algebra style solution
30*t = 2*(t+16). <<<<----==== This equation says that they cover the same distance, but for different time.
Solve for t, which is time counted after the tiger started.
After completing this simple solution you will get the same answer.