SOLUTION: 4. A committee of 5 people is to be formed randomly from a group of 10 women and 6 men. Find the probability that the committee has a) 3 women and 2 men. b) 5 women.

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: 4. A committee of 5 people is to be formed randomly from a group of 10 women and 6 men. Find the probability that the committee has a) 3 women and 2 men. b) 5 women.       Log On

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Question 1102209: 4. A committee of 5 people is to be formed randomly from a group of 10 women and 6 men. Find the probability that the committee has
a) 3 women and 2 men.



b) 5 women.




c) At least 4 women.

Found 2 solutions by Edwin McCravy, Boreal:
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
4. A committee of 5 people is to be formed randomly from a group of 10 women and 6 men. Find the probability that the committee has
a) 3 women and 2 men.

b) 5 women.
c) At least 4 women.
That's the probability of 5 women plus the probability of
4 women and 1 man. Part (b) is the probability of 5 women,
so we only need to add the probability of 4 women and 1 man
to the 3/52 we got in part (b).  





So we add the two:



Edwin

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
The denominator is 16C5=4368
a) numerator is 10C3*6C2=120*15=1800, so that probability is 0.4121
b) 10C5*6C0*1=252, probability is 0.0577
c) 10C4*6C1=210*6=1260, probability is 0.2885 PLUS probability of 5 women, which is 0.0577 for overall probability of 0.3462, adding, and using the numerators above get an exact answer which rounds to the same number.