SOLUTION: Write the first trigonometric function in terms of the second for θ in the given quadrant. sec(θ), sin(θ); θ in Quadrant III. sec(θ)=

Algebra ->  Trigonometry-basics -> SOLUTION: Write the first trigonometric function in terms of the second for θ in the given quadrant. sec(θ), sin(θ); θ in Quadrant III. sec(θ)=       Log On


   

Question 1102185: Write the first trigonometric function in terms of the second for θ in the given quadrant.
sec(θ), sin(θ); θ in Quadrant III.
sec(θ)=
Answer by Alan3354(69443) About Me  (Show Source):
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Write the first trigonometric function in terms of the second for t in the given quadrant.
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sec(t), sin(t); t in Quadrant III.
cos = sqrt(1-sin^2)
sec = 1/cos
sec(t)= 1/sqrt(1-sin^2)
sec = sqrt(1 - sin^2)/(1-sin^2)
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cos and sec are + in Q3