You can put this solution on YOUR website! Write the complex number in polar form with argument θ between 0 and 2π.
-2sqrt2 -2sqrt2i
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The corresponding point is (-2sqrt(2),-2sqrt(2)) which is in QIII
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theta = arctan(-2sqrt(2)/(-2sqrt(2)) = (5/4)pi
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r = sqrt[(-2sqrt2)^2+(-2sqrt(2)^2] = sqrt[8+8] = 4
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Answer:: 4[cos(5pi/4) + isin(5pi/4)]
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Cheers,
Stan H.
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