SOLUTION: A square rock garden with sides of 90 feet is placed in the middle of a circular grass yard. If the circumference of the yard is 520 feet, then how much area is covered by grass?

Algebra ->  Volume -> SOLUTION: A square rock garden with sides of 90 feet is placed in the middle of a circular grass yard. If the circumference of the yard is 520 feet, then how much area is covered by grass?      Log On


   



Question 1102122: A square rock garden with sides of 90 feet is placed in the middle of a circular grass yard. If the circumference of the yard is 520 feet, then how much area is covered by grass?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52866) About Me  (Show Source):
You can put this solution on YOUR website!
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I removed my wrong solution.


Answer by greenestamps(13206) About Me  (Show Source):
You can put this solution on YOUR website!


The other tutor didn't read the problem correctly....

The circular grass yard has a circumference of 520 feet.
The radius of the yard is 520%2F%282%2Api%29+=+260%2Fpi feet, or about 82.76 feet.
The area of the yard is (pi)*r^2: %28pi%29%2A%28260%2Fpi%29%5E2, about 21517.75 square feet.

The square rock garden in the middle has an area of 90^2=8100 square feet.

The area of grass in square feet is 21517.75-8100=13417.75.