SOLUTION: Logan and Zoey went out to dinner. Zoey's dinner bill was $5 more than one-half of Logan's bill. If the two bills combined was $60.26, what was Zoey's dinner bill?

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Question 1102007: Logan and Zoey went out to dinner. Zoey's dinner bill was $5 more than one-half of Logan's bill. If the two bills combined was $60.26, what was Zoey's dinner bill?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
system%28z=L%2F2%2B5%2Cz%2BL=60.26%29

Question asks for z.

2z=L%2B10
2z=%2860.26-z%29%2B10
2z=-z%2B70.26
3z=70.26
highlight%28z=23.42%29

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


While it is useful to know how to solve this problem using formal algebra, it can also be a useful exercise in logical thinking to solve the problem informally.

In the total of $60.26, Zoey's bill was $5 more than one-half of Logan's bill.

So have Zoey pay that "extra" $5; now Zoey's remaining bill is exactly half of Logan's, and the remaining total is $55.26

So divide the $55.26 into 3 equal parts; 1 part is Zoey's and 2 parts are Logan's.
55.26%2F3+=+18.42
So Zoey's bill was $18.42, plus the $5 she paid earlier, for a total of $23.42.