SOLUTION: find the number of distinct permutations of the word BARRACKS

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Question 1101954: find the number of distinct permutations of the word BARRACKS
Answer by ikleyn(52786) About Me  (Show Source):
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The word contains 8 letters;  of them,  the "A" repeats twice, and "R" repeats twice, too.


Thus the number of distinguishable arrangements of the letters is  8%21%2F%282%21%2A2%21%29 = 10080.


First   2!  in the denominator stands to account for repeated  "A".
 

Second  2! in the denominator stands to account for repeated  "R".