SOLUTION: The present ages of a father and son are 40 years and 8 years respectively.How many years ago ,the product of their ages was 105 ? Find it

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Question 1101901: The present ages of a father and son are 40 years and 8 years respectively.How many years ago ,the product of their ages was 105 ? Find it
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
40 father
8 child (son)
x, how many years ago

%2840-x%29%288-x%29=105------(Age difference was still 32).

%283%29%2835%29=105
or
%2835%2A3%29=105

3=8-x using the smaller number
-x=3-8
highlight%28x=5%29---------------five years ago