Question 1101626: Solve the equation
2.7sin(3θ)+0.729=−1.026 for θ. First solve to find the general form of all solutions (using arbitrary integer k), where θ1 and θ2 are angles on [0,2π) with θ1 less than θ2.
θ1=
θ2=
Use the general solutions above to find all the solutions to
2.7sin(3θ)+0.729=−1.026 on the interval [0,2π). (Round your answers to four decimal places. Separate multiple solutions with a comma.)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 2.7sin(3θ)+0.729=−1.026 for θ. First solve to find the general form of all solutions (using arbitrary integer k), where θ1 and θ2 are angles on [0,2π) with θ1 less than θ2.
2.7sin(3t) = -1.026-0.729 = -1.755
sin(3t) = -0.65
3t = -0.7076 or 3t = 3.8492
θ1= -0.2359 radians
θ2= 1.2831 radians
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Cheers,
Stan H.
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Use the general solutions above to find all the solutions to
2.7sin(3θ)+0.729=−1.026 on the interval [0,2π). (Round your answers to four decimal places. Separate multiple solutions with a comma.)
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