SOLUTION: sin^2x = [(sec^2x-1)(1-sin^4x)] / 1+ sin^2x

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Question 1101611: sin^2x = [(sec^2x-1)(1-sin^4x)] / 1+ sin^2x
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Thx for letting us know.