SOLUTION: Three consecutive odd integers whose sum is 417.

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Question 110155: Three consecutive odd integers whose sum is 417.
Answer by elima(1433) About Me  (Show Source):
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Three consecutive odd integers whose sum is 417.
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x = first odd integer
x+2 = second odd integer
x+4 = third odd integer
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x+x+2+x+4=417
3x+6=417
3x=417-6
3x=411
x=137 first odd integer
x+2 = 139 second odd integer
x+4=131 third odd integer
:)