SOLUTION: There are 5 children in the Yoshida Family. The youngest is in the third grade. The oldest is twice as old as the youngest. The Triplets are 4 years younger than the oldest. the p

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Question 1101480: There are 5 children in the Yoshida Family. The youngest is in the third grade. The oldest is twice as old as the youngest. The Triplets are 4 years younger than the oldest. the product of all the childeren's age is 221,184. how old each child?

Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
Grade level and age are not the same thing but are related and depend on where a person lives. If grade 0 (kindergarten) is age 5, then grade 3 would be age 8. 
Children             Age (possibly)

youngest               8

3 in the triplet      16-4=12

oldest                16

Product of all five of these ages: 8%2A12%5E3%2A16=221184------perfect match to description.

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


Let x be the age of the triplets; then the ages of the oldest and youngest are x+4 and x-4.

So the product of all the ages is %28x%5E3%29%28x%2B4%29%28x-4%29.

That product is very close to x^5; so use a calculator or do some estimation to find a value of x for which x^5 is close to 221,184.

221184%5E%281%2F5%29+=+11.72 approximately; so x should be 12.

Now check: %2812%5E3%29%288%29%2816%29+=+221184