SOLUTION: In hospital, there are 12 nurses and 4 doctors,then:
if a committee of 4 nurses and 2 doctors is to be chosen. How many different possibilities are there?
Algebra ->
Probability-and-statistics
-> SOLUTION: In hospital, there are 12 nurses and 4 doctors,then:
if a committee of 4 nurses and 2 doctors is to be chosen. How many different possibilities are there?
Log On
Question 1101393: In hospital, there are 12 nurses and 4 doctors,then:
if a committee of 4 nurses and 2 doctors is to be chosen. How many different possibilities are there?
You can put this solution on YOUR website!
You can choose 4 nurses in 12C4 ways.
You can choose 2 doctors in 4C2 ways.
The number of possible committees of 4 nurses and 2 doctors is thus: 12C4 * 4C2 = 2970