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Question 110133: A bag contains five red balls, three white balls and two green balls. If three balls are selected at random, with replacement, find the probability that the first two are red and third one is green.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A bag contains five red balls, three white balls and two green balls. If three balls are selected at random, with replacement, find the probability that the first two are red and third one is green.
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1st red = 5/10
2nd red = 4/9
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3rd green = 2/8
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P(rrg) = (5/10)(4/9)(2/8) = (4/9)(1/8) = 1/18
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Cheers,
Stan H.
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