SOLUTION: Hi angie had some red and blue beads.40percent of her beads were red. When she lost 50 blue beads,the number of blue beads was reduced by one third its original number of beads

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Question 1101286: Hi
angie had some red and blue beads.40percent of her beads were red. When she lost 50 blue beads,the number of blue beads was reduced by one third its original number of beads
how many beads did she have at the end.
Thanks

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +n+ = original number of beads total
+.6n+ = original number of blue beads
+.4n+ = original number of red beads
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Next, she had:
+.6n+-+50+ blue beads
+.6n+-+50+=+%282%2F3%29%2A%28.6n%29+
+3%2A%28+.6n+-+50+%29+=+2%2A%28+.6n+%29+
+1.8n+-+150+=+1.2n+
+.6n+=+150+
+n+=+250+
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At the end, after losing 50 blue beads,
she had +250+-+50+=+200+ beads
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check:
At beginning:
+.6%2A250+=+150+ blue beads
+.4%2A250+=+100+ red beads
--------------------------------
She lost 50 blue beads, giving her
+150+-+50+=+100+ blue beads at the end
-----------------------------------
+100+=+150+-+%281%2F3%29%2A150+
+100+=+150+-+50+
+100+=+100+
---------------------
Definitely get a 2nd opinion on this.
I could easily have misread it.