SOLUTION: Hi i cant solv this math, can you help me. Su- lin is four years older than mark. Twice Su- lins age plus five times marks ages is equel to 64. what are the ages of Su- Lin and Ma

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Question 1101244: Hi i cant solv this math, can you help me.
Su- lin is four years older than mark. Twice Su- lins age plus five times marks ages is equel to 64. what are the ages of Su- Lin and Mark?
Found 2 solutions by josgarithmetic, math_helper:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
x, Sue-Lin
y, Mark

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Su- lin is four years older than mark. Twice Su- lins age plus five times marks ages is equel to 64.
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system%28x=y%2B4%2C2x%2B5y=64%29

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Let
s = Su-lin's age
m = Mark's age
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We know:
(1) s = m + 4 (from "Su-lin is four years older than Mark.")
(2) 2s + 5m = 64 (from "Twice Su-lin's age plus five times Mark's age is equal to 64.")
Thus we have two equations with two unknowns. Since eq(1) already has s in terms of m, we can substitute "m+4" wherever we see "s" in eq(2). Re-writing eq(2) with this substitution gives:
2(m+4) + 5m = 64
(2m + 8) + 5m = 64
7m = 56
m = 8 —> s = m+4 = 8+4 = 12
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Answer: Su-lin is 12 yrs old, and Mark is 8 yrs old.
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Check:
(1) 12 = 8+4 (ok)
(2) 2(12)+5(8) = 24 + 40 = 64 (ok)