Question 1101120: What is the probability that 19 rolls of a fair die will show 6 fives?
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! we use the binomial probability formula
:
Probability(P) (k successes in n trials) = nCk * p^k * (1-p)^(n-k), where nCk = n! / (k! * (n-k)!)
:
for this problem n=19, k=6, p = 1/6
:
Note p = 1/6 is the probability of rolling a 5 with a six sided fair die
:
P ( 6 successes in 19 trials ) = 19C6 * (1/6)^6 * (1-(1/6))^(19-6) = 0.0543 approximately 0.05
:
|
|
|
