SOLUTION: There were​ 36,000 people at a ballgame in Los Angeles. The​ day's receipts from​ $12 reserved seats and​ $6 general-admission seats were​ $258,000 Ho

Algebra ->  Test -> SOLUTION: There were​ 36,000 people at a ballgame in Los Angeles. The​ day's receipts from​ $12 reserved seats and​ $6 general-admission seats were​ $258,000 Ho      Log On


   



Question 1100866: There were​ 36,000 people at a ballgame in Los Angeles. The​ day's receipts from​ $12 reserved seats and​ $6 general-admission seats were​ $258,000 How many of each type of seat were​ sold?
Found 3 solutions by richwmiller, TeachMath, josgarithmetic:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=36000,
12*x+6*y=258000
x=36000-y
12*(36000-y)+6*y=258000
432000-12y+6*y=258000
-6*y=-174000
y=29000
x=36000-y
x=7000 at 12 and y=29000 at 6
check
7000+29000=36000
12*x+6*y=258000
12*7000+6*29000=258000
84000+174000=258000
258000=258000
ok
codetick
Warning: I am sick in bed. Double check my work.

Answer by TeachMath(96) About Me  (Show Source):
You can put this solution on YOUR website!
u're not only sick in bed...u're sick in the head, so stop trying 2 help cuz ur not helping.
must be some old grumpy geezer having esteem issues since u love to be rude and disrespectful to people. i hope to meet u one day

Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
r, Reserved seats
g, General admission seats
system%286g%2B12r=258000%2Cg%2Br=36000%29

g=36000-r
-
6%2836000-r%29%2B12r=258000--------one equation in one unknown variable
6%2A36000-6r%2B12r=258000
6r%2B6%2A36000=258000
r%2B36000=43000
highlight%28r=7000%29
-
highlight%28g=29000%29