Question 1100752: You have a jar containing 55 coins, consisting entirely of nickels and quarters, worth a total of $7.15. How many quarters are in the jar? Found 2 solutions by Fombitz, ikleyn:Answer by Fombitz(32388) (Show Source):
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You have a jar containing 55 coins, consisting entirely of nickels and quarters, worth a total of $7.15. How many quarters are in the jar?
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Let N be the number of nickels.
Then the number of quarters is (55-N).
The nickels contribute 5N cents to the total.
The quarters contribute 25*(55-N) cents to the total.
Thus the total is 5N + 25*(55-N) cents.
According to he condition, it is 715 cents, so you have this "money" equation
5N + 25*(55-N) = 715.
It is your basic equations.
As soon as you got this equation and understood it, the setup part is completed.
To solve the equation, simplify it step by step
5N + 1375 - 25N = 715 ====> -20N = 715 - 1375 = -660 ====> N = = 33.
Answer. 33 nickels and 55-33 = 22 quarters.
Check. 33*5 + 22*25 = 715 cents. ! Correct !
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