

The discriminant, which is b2-4ac, must be zero in
order for this equation to have just one real root:






So we set this discriminant equal to zero:


Solve that either of two ways:
First way:


Add 16 to both sides:


Use the principle of square roots:


<-- the answers
Second way:


Factor the left side as the difference of two squares:


k-4 = 0; k+4 = 0
k = 4; k = -4 <-- the answers
-------
To prove that 

just has one
real root when k = 4 or k = -4, we substitute in


Substituting 4 for k:


Divide both sides by 2


Factor:


x-1 = 0; x-1 = 0
x = 1 x = 1 <-- just 1 root, 1
---


Substituting -4 for k:




Divide both sides by 2


Factor:


x+1 = 0; x+1 = 0
x = -1 x = -1 <-- just 1 root, -1
Edwin