

The discriminant, which is b2-4ac, must be zero in 
order for this equation to have just one real root:






So we set this discriminant equal to zero:


Solve that either of two ways:
First way:


Add 16 to both sides:


Use the principle of square roots:


   <-- the answers 
Second way:


Factor the left side as the difference of two squares:


k-4 = 0;  k+4 = 0
  k = 4;    k = -4   <-- the answers
-------
To prove that 

 just has one
real root when k = 4 or k = -4, we substitute in


Substituting 4 for k:


Divide both sides by 2


Factor:


x-1 = 0; x-1 = 0
  x = 1   x = 1   <-- just 1 root, 1
---


Substituting -4 for k:




Divide both sides by 2


Factor:


x+1 = 0;  x+1 = 0
  x = -1    x = -1   <-- just 1 root, -1
Edwin