SOLUTION: In 2009, a consulting firm surveyed a random sample of 700 U.S. businesses and found that 28% of them were owned by women.
Create a 90% confidence interval for the true proport
Algebra ->
Probability-and-statistics
-> SOLUTION: In 2009, a consulting firm surveyed a random sample of 700 U.S. businesses and found that 28% of them were owned by women.
Create a 90% confidence interval for the true proport
Log On
Question 1100566: In 2009, a consulting firm surveyed a random sample of 700 U.S. businesses and found that 28% of them were owned by women.
Create a 90% confidence interval for the true proportion of U.S. businesses that are owned by women.
You can put this solution on YOUR website! In 2009, a consulting firm surveyed a random sample of 700 U.S. businesses and found that 28% of them were owned by women.
Create a 90% confidence interval for the true proportion of U.S. businesses that are owned by women.
-----
sample proportion:: 0.28
ME = z*sqrt(pq/n) = 1.645*sqrt[0.28*0.72/700) = 0.0279
------
90% CI: 0.28-0.0279 < p < 0.28+0.0279
90% CI: 0.2521 < p < 0.3079
-----------
Cheers,
Stan H.
-----------