SOLUTION: The length of a rectangle is 2 ft longer than its width. If the perimeter of the rectangle is 36 ft , find its area.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The length of a rectangle is 2 ft longer than its width. If the perimeter of the rectangle is 36 ft , find its area.      Log On


   



Question 1100521: The length of a rectangle is
2

ft
longer than its width.
If the perimeter of the rectangle is
36

ft
, find its area.

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Width=x
length=x+2
perimeter=2(width)+2(length)=36
2x+2x+4=36
4x+4=36
4x=32
x=8 feet width
x+2=10 feet length.
Area is length*width=80 ft^2.