SOLUTION: The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle. (I need to show the equation, than
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Question 110050: The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle. (I need to show the equation, thanks very much.) Answer by BrittanyM(80) (Show Source):
You can put this solution on YOUR website! In order to solve this problem, we must begin with the formula for the perimeter:
P=2L + 2W
Where the legnth is twice the width plus two (L=2W+2)
Since you know that the perimeter is 34,
substitute 34 for P and 2W+2 for L.
34=2(2W+2)+2W
34=4W+4+2w
34=6W+4
30=6W
w=5
Now solve the equation for L, substituting 5 for W.
34=2L+2(5)
24=2L
L=12
So the width is 5 and the legnth is 12. :)
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