SOLUTION: How do you rewrite the following logs as a sum, difference, or product: a) ln(3x-2/x+1) and b) ln(x^5(x+7))? I think the first one becomes a difference and the second becomes a sum

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: How do you rewrite the following logs as a sum, difference, or product: a) ln(3x-2/x+1) and b) ln(x^5(x+7))? I think the first one becomes a difference and the second becomes a sum      Log On


   

Question 1100332: How do you rewrite the following logs as a sum, difference, or product: a) ln(3x-2/x+1) and b) ln(x^5(x+7))? I think the first one becomes a difference and the second becomes a sum but I am not exactly sure. Thank you!
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
rules:

log(a/b) = log(a) - log(b)

log (a*b) = log(a) + log(b)

log(a^b) = b * log(a)

a)

ln((3x-2)/(x+1)) = ln(3x-2) - ln(x+1)

b)

ln((x^5)(x+7)) = ln(x^5) + ln(x+7) = 5*ln(x) + ln(x+7)