SOLUTION: The woodland jumping frog can hop suprisingly long distances given it’s small size. A long hop can be modeled by y=-2/9x[x-6] how far can a woodland jumping frog hop
How high can
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How high can
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Question 1100324: The woodland jumping frog can hop suprisingly long distances given it’s small size. A long hop can be modeled by y=-2/9x[x-6] how far can a woodland jumping frog hop
How high can it hop Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! This is y=-(2/9)(x^2-6x)
or y=-(2/9)x+(12/9)x
the x value for the vertex (highest point) is -b/2a or -(12/9)/-(4/9), which is 3 feet. y(3)=-(2/9)(-9)=2 feet ANSWER
The vertex is symmetrical, so if the starting point is 0 feet, the ending point is 6 feet. ANSWER
OR y=(-2/9)(x)(x-6)=0
x=0 and 6.
