SOLUTION: A clothing store buyer purchased some designer jeans at $22 a pair. Then she bought 20 more than half that number of another type of designer jeans at $26 a pair. If she spent $110

Algebra ->  Finance -> SOLUTION: A clothing store buyer purchased some designer jeans at $22 a pair. Then she bought 20 more than half that number of another type of designer jeans at $26 a pair. If she spent $110      Log On


   



Question 1100308: A clothing store buyer purchased some designer jeans at $22 a pair. Then she bought 20 more than half that number of another type of designer jeans at $26 a pair. If she spent $110 more on the first type, how many pairs pf each type did she buy?
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!

Let x be the number of pairs of the first type.

The number she bought of the second type was 20 more than one-half of that number: (1/2)x+20.

The first type cost $22 a pair; the total cost of them was 22%28x%29.
The second type cost $26 a pair; the total cost of them was 26%28%281%2F2%29x%2B20%29.

The total cost of the first type was 110 more than the total cost of the second type:
22x+=+26%28%281%2F2%29x%2B20%29%2B110
22x+=+13x%2B520%2B110
9x+=+630
x+=+70

She bought 70 pairs of the first type.
The number of pairs of the second type that she bought was (1/2)*70+20 = 55.