SOLUTION: Sum of two positive number is 70.if The quotient obtained on dividing first number by other is 4.find number.

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Question 1100048: Sum of two positive number is 70.if The quotient obtained on dividing first number by other is 4.find number.
Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
a + b = 70
a / b = 4

solve for a in the first equation to get a = 70 - b

replace a in the second equation to get (70 - b) / b = 4

(70 - b) / b is the same as 70/b - b/b.

second equation becomes 70/b - b/b = 4

since b/b = 1, formula becomes 70/b - 1 = 4

add 1 to both sides of the equation to get 70/b = 5

multiply both sides of the equation by b to get 70 = 5b

solve for b to get b = 70/5 = 14

when b = 14, a + b = 70 becomes a + 14 = 70

solve for a to get a = 70 - 14 = 56

you have a = 56 and b = 14.

a + b = 56 + 14 = 70
a / b = 56 / 14 = 4

solution is that the first number is 56 and the second number is 14.

it might have been easier to solve for a in the second equation.

your two equations are, once again:

a + b = 70
a / b = 4

solve for a in the second equation to get a = 4b

replace a in the first equation to get 4b + b = 70

solve for b to get b = 70/5 = 14.

same answer but with less pain.

Answer by ikleyn(52817) (Show Source):
You can put this solution on YOUR website!
.

A + B = 70, A/B = 4 ====> A = 4*B. Substitute it into A + B = 70. You will get 4B + B = 70 ====>. 5B = 70 ====> B = = 14. Answer. B = 14, A = 70-14 = 56. The numbers are 56 and 14.