SOLUTION: what percent of the number should be subtracted to get the original number back if we add 10% of a number itself?

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Question 1099951: what percent of the number should be subtracted to get the original number back if we add 10% of a number itself?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+n+%2B+.1n+=+1.1n+
Let +x+ = the percent of +1.1n+
to be subtracted to give me +n+
+1.1n+-+%28+x%2F100+%29%2A1.1n+=+n+
+1.1n%2A%28+1+-+x%2F100+%29+=+n+
+1.1%2A%28+1+-+x%2F100+%29+=+1+
+1+-+x%2F100+=+1%2F1.1+
+x%2F100+=+1+-+1%2F1.1+
+x%2F100+=+1+-+.90909+
+x%2F100+=+.090909+
+x+=+9.091+
9.091% of 1.1n must be subtracted to get +n+
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