SOLUTION: 10x^5+11x^4+3x^3 I have to factor by grouping and ac method please help I don’t know what I’m doing wrong

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Question 1099933: 10x^5+11x^4+3x^3 I have to factor by grouping and ac method please help I don’t know what I’m doing wrong
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
First step - take out common factors:
10x%5E5%2B11x%5E4%2B3x%5E3=x%5E3%2810x%5E2%2B11x%2B3%29

Now you have to factor 10x%5E2%2B11x%2B3 .
I assume you were told that you could split the middle term into two terms,
and then "factor by grouping",
finding the coefficients of the split terms as factors of ac ,
where a is the coefficient of x%5E2 and c is the independent term.
a=10 and c=3 , so ac=10%2A3=30 .
You want to find a pair of numbers (factors of 30)
whose product is 30 , and whose sum is 11 .
Because the product and the sum are positive,
you know that the two factors are positive.
Nice, we do not have to worry about negative numbers.
The pairs of numbers that give 30 as a product are
1%2A30=30 ,
2%2A15=30 ,
3%2A10=30 , and
5%2A6=30 .
So, we pick 5 and 6 ,
because they add to the middle term: 5%2B6=11 .
Writing only the part to be factored,
.
So, after all that work,
10x%5E5%2B11x%5E4%2B3x%5E3=highlight%28x%5E3%285x%2B3%29%282x%2B1%29%29 .