SOLUTION: find x: logbase3 (2x+1)=logbase3(x-2)-logbase3(3)

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Question 1099872: find x:
logbase3 (2x+1)=logbase3(x-2)-logbase3(3)
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!

The bases are the same for every term in the equation, so using rules of logarithms we can see
2x%2B1+=+%28x-2%29%2F3
6x%2B3+=+x-2
5x+=+-5
x+=+-1

Algebraically, the only possible solution is x = -1; however, that makes the original equation
log%281%29+=+log%28-3%29+-+log%283%29
and that equation is invalid because log(-3) is undefined.

So there is no value of x that makes the equation true.