Question 1099852: Hello, I would like some help solving this trigonometry problem!
Solve the triangle if possible:
C=63° 10', c=32.4, b=24.9
I'm trying to figure out if there are one or two solutions for the triangle= B, A, a
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39623)   (Show Source):
You can put this solution on YOUR website! Try drawing the triangle. 63 degree is opposite of 32.4 unit length. The 24.9 unit length is EITHER opposite of point A, or opposite of point B. Now, angle at point A depends on what you choose for angle at B.
Another way; choose one of the points as angle A. This angle is not fixed. It may be made acute or Right, or obtuse. Whatever you choose for A, you can solve for B, and use Law of Sines to get b and a.
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website!
Hello, I would like some help solving this trigonometry problem!
Solve the triangle if possible:
C=63° 10', c=32.4, b=24.9
I'm trying to figure out if there are one or two solutions for the triangle= B, A, a
1) Use law of sines to find measure of ∡B
2) With ∡s C & B known ∡A can be found
3) With ∡A known, again use law of sines to find side a.
4) Find the SUM of ∡C and the REFERENCE angle of ∡B
5) If the sum in 4 is < 180o, then 2 DISTINCT TRIANGLES can be formed, but if the SUM > 180o, then ONLY 1 DISTINCT TRIANGLE can be formed using the given values.
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