SOLUTION: What is the equation of the line written in standard form that passes through the point (-3, 4) and is perpendicular to the line 3x + 2y = 5?

Algebra ->  Coordinate-system -> SOLUTION: What is the equation of the line written in standard form that passes through the point (-3, 4) and is perpendicular to the line 3x + 2y = 5?       Log On


   

Question 1099819: What is the equation of the line written in standard form that passes through the point
(-3, 4) and is perpendicular to the line 3x + 2y = 5?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
3x%2B2y=5
2y=-3x%2B5
y=-%283%2F2%29x%2B5%2F2
Perpendicular lines have slopes that are negative reciprocals.
-%283%2F2%29%2Am%5Bp%5D=-1
m%5Bp%5D=2%2F3
So using the point slope form of a line,
y-4=%282%2F3%29%28x%2B3%29
3y-12=2x%2B6
-2x%2B3y=18
2x-3y=-18
.
.
.
.
.
.
.