SOLUTION: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 20 square feet, find the length of the sides of the poster

Algebra ->  Triangles -> SOLUTION: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 20 square feet, find the length of the sides of the poster      Log On


   

Question 1099778: A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 20 square feet, find the length of the sides of the poster and the sign
Answer by ikleyn(52889) About Me  (Show Source):
You can put this solution on YOUR website!
.
x%5E2 - %28x-2%29%5E2 = 20  ====>

x%5E2+-+%28x%5E2+-4x+%2B+4%29 = 20  ====>

4x = 20 + 4 = 24   ====>  x = 6.


Answer.  The larger square has the side length of 6 feet.

         The smaller square has the side length of 4 feet.

         6^2 - 4^2 = 36 - 16 = 20.   ! Correct !

Solved.