SOLUTION: The probability that a person, living in Minneapolis owns a cat is
estimated to be 0.141. Find the probability that the ninth person
randomly interviewed in Minneapolis is the
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-> SOLUTION: The probability that a person, living in Minneapolis owns a cat is
estimated to be 0.141. Find the probability that the ninth person
randomly interviewed in Minneapolis is the
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Question 1099690: The probability that a person, living in Minneapolis owns a cat is
estimated to be 0.141. Find the probability that the ninth person
randomly interviewed in Minneapolis is the eighth one to own a cat. Answer by Edwin McCravy(20060) (Show Source):
That's a binomial probability problem
where:
1. Exactly 7 of the first 8 people interviewed had a cat.
and
2. The 9th person interviewed owned a cat.
Probability that exactly 7 of the first 8 people interviewed
had a cat
n = 8
p = 0.141
x = 7
0.0000076140713
Probability that the 9th person interviewed had a cat:
That's 0.141
Since it's "and" we multiply the probabilities:
Answer (0.0000076140713)(0.141) = 0.000001073584053
It's extremely unlikely!
Edwin
