SOLUTION: in 2003, the price of a certain automobile was approximately $32,500.00 with a depreciation of $2,050.00 per year. After how many years will the car's value be $7,900.00? a) Write

Algebra ->  Finance -> SOLUTION: in 2003, the price of a certain automobile was approximately $32,500.00 with a depreciation of $2,050.00 per year. After how many years will the car's value be $7,900.00? a) Write      Log On


   



Question 1099621: in 2003, the price of a certain automobile was approximately $32,500.00 with a depreciation of $2,050.00 per year. After how many years will the car's value be $7,900.00?
a) Write an equation to model the problem. Let t represent the number of years after 2003.
Answer:
b) Solve the equation to answer the question above. (Note: Include the units, in this case years.)
Answer:

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
P%28t%29=32500-2050n
So find t when P%28t%29=7900,
32500-2050t=7900
-2050t=-24600
t=24600%2F2050
Solve for t.
Then add t to 2003 to get the year.