SOLUTION: A child’s piggy bank contains 35 coins and a total of $6.25. The bank contains quarters,
dimes and nickels. There are twice as many dimes as there are nickles. How many of
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dimes and nickels. There are twice as many dimes as there are nickles. How many of
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Question 1099460: A child’s piggy bank contains 35 coins and a total of $6.25. The bank contains quarters,
dimes and nickels. There are twice as many dimes as there are nickles. How many of
each coin is in the bank?
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A child’s piggy bank contains 35 coins and a total of $6.25. The bank contains quarters, dimes and nickels.
There are twice as many dimes as there are nickles. How many of each coin is in the bank?
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Let N be the number of nickels.
Then the number of dimes is 2N, according to the condition.
Hence, the number of quarters is (35-N-2N) = (35-3N).
The nickels contribute 5N cents towards the total.
The dimes contribute 10*(2N) = 20N cents towards the total.
The quarters contribute 25*(35-3N) cents towards the total.
So, your balance equation is
5N + 20N + 25*(35-3N) = 625 cents. (<<<---=== you counted all the cents)
Simplify and solve for N step by step.
25N + 875 - 75N = 625 ====> -50N = 625 - 875 = -250 ====> N = = 5.
Answer. 5 nickels, 10 dimes and 35-5-10 = 20 quarters.
Check. Can you check it on your own ??
The lesson to learn from this solution:
This problem is FOR ONE UNKNOWN.
Therefore, I made all efforts from my side to solve it as the problem in ONE UNKNOWN.
You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.
Read them and become an expert in solution of coin problems.
