SOLUTION: A piece of metal is 1 ft. long, 6 in. wide, and 4 in. thick, and weighs 3037 oz. avoirdupois. It is composed of an alloy of gold and copper. Determine percentage of gold. Gold

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Question 1099291: A piece of metal is 1 ft. long, 6 in. wide, and 4 in. thick, and weighs 3037 oz. avoirdupois. It is composed of an alloy of gold and copper. Determine percentage of gold.
Gold weighs .70 lbs. per cu. in.
Copper weighs .32 lbs. per cu. in.
Not sure how to solve. Non-homework.

Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
cubic inches: 12*6*4=288
x=Au (pounds)
288-x=Cu (pounds)
density of metal is 3037/288=10.545 lb/in^3
Weight in pounds is 189.81 pounds
.70x+.32(288-x)=189.81
.38x+92.16=189.81
.38x=97.65
x=256.98 in^3 gold
288-x=31.02 in^3 copper
89.2% gold

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
A piece of metal is 1 ft. long, 6 in. wide, and 4 in. thick, and weighs 3037 oz. avoirdupois.
It is composed of an alloy of gold and copper. Determine percentage of gold.
Gold weighs .70 lbs. per cu. in.
Copper weighs .32 lbs. per cu. in.
~~~~~~~~~~~~~~~~~~~~~~

When they ask  "Determine percentage of gold",  they mean the ratio of the gold contents by  WEIGHT  to the total  WEIGHT  of the alloy;
the ratio, expressed as percentage.

My first step is to convert 3037 oz. avoirdupois to pounds:


   Wikipedia says   https://en.wikipedia.org/wiki/Avoirdupois

      The avoirdupois system is a measurement system of weights which uses pounds and ounces as units.
      It was first commonly used in the 13th century and was updated in 1959.

      Shortly speaking, "1 oz. avoirdupois" = 1%2F16 of a pound.


So,  3037 oz. avoirdupois = %281%2F6%29%2A3037 = 189.8125 pounds.

Then the density of the alloy is  189.8125%2F%2812%2A6%2A4%29 = 0.659 lb/in^3.


Now, having the weight and the density expressed in consistent units, I can write the system of equations.


Let  0 <= x <= 1 be the fraction (by the weight) of gold in the alloy (i.e. percentage is 100x).

Then the weight fraction of copper is (1-x), obviously.


Then the "fraction" equation is

    D%5Bgold%5D%2Ax + D%5Bcopper%5D%2A%281-x%29 = D%5Balloy%5D,   


where D stands for density, or


    0.70*x + 0.32*(1-x) = 0.659.


Simplify and solve for x:

    0.70x + 0.32 - 0.32x = 0.659  ====>  0.38x = 0.659 - 0.32 = 0.339  ====>  x = 0.339%2F0.38 = 0.8921.


Thus the gold fraction by the weight is  0.8921,  or  89.21%.

Solved.