SOLUTION: Students of a class are made to stand in rows.
if one student is Extra in each row, there would be 2 rows less in the arrangement.
if one student is less in each row,there woul
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-> SOLUTION: Students of a class are made to stand in rows.
if one student is Extra in each row, there would be 2 rows less in the arrangement.
if one student is less in each row,there woul
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Question 1099228: Students of a class are made to stand in rows.
if one student is Extra in each row, there would be 2 rows less in the arrangement.
if one student is less in each row,there would be 3 rows more.
find the number of students in the class Found 2 solutions by ikleyn, Edwin McCravy:Answer by ikleyn(52781) (Show Source):
The original arrangement of the class is S students in each of R rows.
So SR = the number of students in the class.
The first new arrangement of the class is S+1 students in each of R-2 rows.
So (S+1)(R-2) also equals the number of students in the class.
The second new arrangement of the class is S-1 students in each of R+3 rows.
So (S-1)(R+3) also equals the students in the class.
Since the number of students is the same under each of the three
arrangements,
SR = (S+1)(R-2) = (S-1)(R+3)
SR = SR-2S+R-2 = SR+3S-R-3
Subtract SR from all three sides:
0 = -2S+R-2 = 3S-R-3
So each of those are equal to 0
-2S+R-2 = 0
3S-R-3 = 0
Adding the two equations term by term:
S -5 = 0
S = 5
Substituting S = 5 in -2S+R-2 = 0
-2(5)+R-2 = 0
-10+R-2 = 0
-12+R = 0
R = 12
So the number of students is SR = (5)(12) = 60
Checking.
In the original arrangement there were 5 students in each of 12 rows.
In the first new arrangement there were 6 students in each of 10 rows.
That's 1 student more and 2 rows less than in the original arrangement.
In the second new arrangement there were 4 students in each of 15 rows.
That's 1 student less and 3 rows more than in the original arrangement.
Edwin