Question 1098899: Bobs has 8 more dimes than quarters together they total $8.50 how many of each does he have Found 2 solutions by Boreal, ikleyn:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x=quarters
x+8=dimes
.25x+0.10(x+8)=8.50
.25x+0.10x+0.80=8.50
.35x=7.70
x=22 quarters ($5.50)
x+8=30 dimes ($3.00)
They add to $8.50
For a minute, take off 8 dimes from the collection.
Then your updated collection consists of equal number of dimes and quarters and is worth 850-80 = 770 cents.
But now you can combine your coins in pairs containing (1 dime + 1 quarter) each.
Each pair is worth 35 cents (= 10 + 25), so the number of such pairs is = 22.
Answer. There are 22 quarters and 22+8 = 30 dimes in the original collection.
Solved.
As you see, I did not forget to return back that 8 dimes I took off at the beginning.
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