SOLUTION: 5^x=3-5^(2x)
Please help! Sorry I've been asking a lot of questions but I have a test tomorrow and we had a supply teacher who didn't know the material. The teacher left handout
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: 5^x=3-5^(2x)
Please help! Sorry I've been asking a lot of questions but I have a test tomorrow and we had a supply teacher who didn't know the material. The teacher left handout
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Question 1098778: 5^x=3-5^(2x)
Please help! Sorry I've been asking a lot of questions but I have a test tomorrow and we had a supply teacher who didn't know the material. The teacher left handouts without a lesson so I've been figuring things out on my own. More likely I'm really tired and can't concentrate. Sorry for the inconvenience. Found 2 solutions by greenestamps, ikleyn:Answer by greenestamps(13209) (Show Source):
You can put this solution on YOUR website! With the "5^2x" and "5^x" terms in the equation, this can be viewed as a "quadratic" equation in which the "variable" is 5^x, because .
So rewrite the equation as
If it helps ease the confusion, you can define a new variable and write the equation as
The quadratic does not factor, so use the quadratic formula:
Since 5^x is never negative, we choose the positive solution:
Then to solve for x, since it is an exponent, we take logs of both sides: