Question 1098601: Your statistics instructor claims that 60 percent of the students who take her Elementary Statistics class go through life feeling more enriched. For some reason that she can't quite figure out, most people don't believe her. You decide to check this out on your own. You randomly survey 64 of her past Elementary Statistics students and find that 34 feel more enriched as a result of her class. Now, what do you think?
I can't for the life of me figure this out step by step
Answer by MathTherapy(10552)   (Show Source):
You can put this solution on YOUR website! Your statistics instructor claims that 60 percent of the students who take her Elementary Statistics class go through life feeling more enriched. For some reason that she can't quite figure out, most people don't believe her. You decide to check this out on your own. You randomly survey 64 of her past Elementary Statistics students and find that 34 feel more enriched as a result of her class. Now, what do you think?
I can't for the life of me figure this out step by step
You need to do a hypothesis test for population proportion, with: 
x = 34, n = 64, and p-hat = 
p (probability of success): 60%, or 0.6
q (probability of failure): 1 - p = .4
As x = 34, we find the Z-test Statistic, and then use that value to find the  , or P-value
Z-test Statistic =  .
The 2-tailed P-Value for a Z-test Statistic of - 1.12 is .2628.
The P-value of .2628 > all significance levels that're usually used (.05, or 5%, .1, or 10%, and .005, or .5%).
Therefore, with P-Value > ANY chosen significance level, then we: Fail to Reject Null, and conclude that there's INSUFFICIENT EVIDENCE
to reject her claim that 60 percent of the students who take her Elementary Statistics class go through life feeling more enriched.
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