SOLUTION: Two equal sized vats, A and B containing 1000L of oil, are slowly being drained. Given that each Vat is being drained at a constant rate and that it takes 4 hours to drain Vat A co

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Two equal sized vats, A and B containing 1000L of oil, are slowly being drained. Given that each Vat is being drained at a constant rate and that it takes 4 hours to drain Vat A co      Log On


   



Question 1098556: Two equal sized vats, A and B containing 1000L of oil, are slowly being drained. Given that each Vat is being drained at a constant rate and that it takes 4 hours to drain Vat A completely and 5 hours to drain Vat B completely, find the time at which the amount of oil in Vat B is four times the amount of oil in Vat A.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
1000/4=250 L/h
1000/5=200 L/h
4(1000 - 250t)=1000 - 200t
4000 - 1000t=1000 - 200t
800t=3000
t=3.75 hours