SOLUTION: There were 271 tickets sold for a basketball game. The activity​ cardholders' tickets cost ​$1.25 and the​ non-cardholders' tickets cost ​$2.25. The total a

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: There were 271 tickets sold for a basketball game. The activity​ cardholders' tickets cost ​$1.25 and the​ non-cardholders' tickets cost ​$2.25. The total a      Log On


   

Question 1098523: There were 271 tickets sold for a basketball game. The activity​ cardholders' tickets cost ​$1.25 and the​ non-cardholders' tickets cost ​$2.25. The total amount of money collected was ​$569.75 How many of each kind of ticket were​ sold?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
C+NC=271; C=cardholder, NC=non-cardholder
1.25C+2.25NC=569.75
but C=271-NC
Therefore, 1.25(271-NC)+2.25NC=569.75
338.75-1.25NC+2.25NC=569.75
NC=231 (cost is 519.75)
C=40 (cost is 50)
Total is $569.75