SOLUTION: Let f(x)=16-x^ and g(x)=4-x. Find f(x)+g(x).

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Question 109852: Let f(x)=16-x^ and g(x)=4-x. Find f(x)+g(x).
Found 2 solutions by Edwin McCravy, MathLover1:
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!


Just add their right sides:

f(x) + g(x) = "right side of f(x)" + "right side of g(x)" 

f(x) + g(x) = (16-x²) + (4-x)

Now simplify:

f(x) + g(x) = 16 - x² + 4 - x

f(x) + g(x) = 20 - x² - x

Arranging in descending order

f(x) + g(x) = -x² - x + 20

Edwin


Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Let f(x) = 16 - x^ ….do you have here x%5E2 or x?
if you have x%5E2, then we have:
+f%28x%29+=+16+-+x%5E+2
and g%28x%29+=++4+-+x
to find f%28x%29+%2B+g%28x%29.....substitute values for f%28x%29 and g%28x%29
f%28x%29+%2B+g%28x%29+=+%2816+-x%5E+2%29+%2B+%284-x%29.....
f%28x%29+%2B+g%28x%29+=+16+-x%5E+2+%2B+4+-+x
f%28x%29+%2B+g%28x%29+=+-+x%5E2+-+x+%2B+20
if you have x, then we will have:
f%28x%29+%2B+g%28x%29+=+%2816+-x%29+%2B+%284+-+x%29.....
f%28x%29+%2B+g%28x%29+=+16+-x+%2B+4+-+x+.....
f%28x%29+%2B+g%28x%29+=+-+2x+%2B++20+.....