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| Question 1098055:  Out of 6 physicists and 6 chemists, a committee consisting of 3
 physicists and 2 chemists is to be formed. In how many ways
 can this be done if: two particular physicists cannot be on
 the committee together?
 Answer by Edwin McCravy(20064)
      (Show Source): 
You can put this solution on YOUR website! Out of 6 physicists and 6 chemists, a committee consisting of 3 physicists and 2 chemists is to be formed. In how many ways
 can this be done if: two particular physicists cannot be on
 the committee together?
 
 
So there are 2 "restricted" physicists and 4 non-"restricted" physicists.
So the committee consists of either:
Case 1: 1 restricted physicist, 2 non-resticted physicists, and 2 chemists.  
Choose the 1 restricted physicist in 2C1 ways.  (2 choose 1)
Choose the 2 non-restricted physicist in 4C2 ways. (4 choose 2)
Choose the 2 chemists in 6C2 ways. (6 choose 2)
That's (2C1)(4C2)(8C2).
          OR
Case 2: 3 non-restricted physicists, and 2 chemists.  
Choose the 3 non-restricted physicist in 4C3 ways. (4 choose 3)
Choose the 2 chemists in 6C2 ways. (6 choose 2)
That's (4C3)(6C2).
Total for both cases:  (2C1)(4C2)(8C2) + (4C3)(6C2)
Edwin
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