SOLUTION: y varies jointly as a and b, and inversely as the square root of c. y=12 when a=3, b=2, and c =25. find y when a=5, b=3, and c=9.

Algebra ->  Proportions -> SOLUTION: y varies jointly as a and b, and inversely as the square root of c. y=12 when a=3, b=2, and c =25. find y when a=5, b=3, and c=9.      Log On


   

Question 1097538: y varies jointly as a and b, and inversely as the square root of c. y=12 when a=3, b=2, and c =25. find y when a=5, b=3, and c=9.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
y varies jointly as a and b, and inversely as the square root of c. y=12 when a=3, b=2, and c =25. find y when a=5, b=3, and c=9.
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y = k*ab/sqrt(c) where k is a constant.
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Solve for k
Then calculate.
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PS All these problems are similar.
Don't post any more of them.