SOLUTION: A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 11 days. (This means that every 11 days the population d

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 11 days. (This means that every 11 days the population d      Log On


   

Question 1097490: A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 11 days. (This means that every 11 days the population decreases by half.) Write a function that represents the amount of bacteria in the population after days
Found 2 solutions by richwmiller, josgarithmetic:
Answer by richwmiller(17219) About Me  (Show Source):
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missing information!!

Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
x days

Initial, 1175%2A%281%2F2%29%5E%280%2F11%29=1175%2A%281%2F2%29%5E0=1175

After 11 days, 1175%2A%281%2F2%29%5E%2811%2F11%29=1175%281%2F2%29%5E1=1175%2A%281%2F2%29

After x days, highlight%281175%2A%281%2F2%29%5E%28x%2F11%29%29

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Usually we see exercises for bacteria exponential growth; not exponential decay.