SOLUTION: Find a rational number and irrational number between the two given numbers: 6.21744...6.22746

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Question 1097476: Find a rational number and irrational number between the two given numbers:
6.21744...6.22746

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
To find a rational number, note that
6.21744 < 6.22000 < 6.22746
and 6.22 can be written 622/100 or reduced to +highlight%28311%2F50%29+.
EDIT: I had accidentally typed out an extra zero to make 1000 in the denominator. Edited to fix it. Sorry about that.

For the irrational number, let's call it x
+6.21744+%3C+x+%3C+6.22746 and x irrational (so x^2 is not an integer)
+6217.44+%3C+1000x+%3C+6227.46+
+%286217.44%29%5E2+%3C+1000000x%5E2+%3C+%286227.46%29%5E2+
Now if we restrict our range to:
++%286218%29%5E2+%3C+1000000x%5E2+%3C+%286219%29%5E2+
We can just pick an integer between +6218%5E2+ and +6219%5E2+ (excluding endpoints) and
set +1000000x%5E2+ to that:
For example, one solution is:
+1000000x%5E2+=+6218%5E2+%2B+1+=+38663525+
++x%5E2+=+38663525%2F1000000+
+highlight%28x+=+sqrt%2838.663525%29%29+ is irrational and is approximately 6.2180001, which falls between the limits given. This is just one of many, many solutions.

The reason it is irrational is every integer between +%286218%29%5E2+=+38663524+ and +%286219%29%5E2+=+38675961+, excluding endpoints, can not be a perfect square, and hence its square root is irrational.