SOLUTION: Write the equation of the line that is perpendicular to y=-10/11x+53/11 and passes through (-10,-10)

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Question 1097467: Write the equation of the line that is perpendicular to y=-10/11x+53/11 and passes through (-10,-10)
Found 3 solutions by Alan3354, josgarithmetic, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Write the equation of the line that is perpendicular to y=-10/11x+53/11 and passes through (-10,-10)
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Step 1, find the slope of the given line. Call it m1.
Step 2, the slope of lines perpendicular is the negative inverse of m1, = -1/m1. Call it m2.
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Step 3, use y-y1 = m2*(x-x1) where (x1,y1) is the point.
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The practice will do you good.
I don't need any.

Answer by josgarithmetic(39629) About Me  (Show Source):
Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

Write the equation of the line that is perpendicular to y=-10/11x+53/11 and passes through (-10,-10)
Slope of given line: -+10%2F11

Slope of perpendicular line: 11%2F10

Equation requested: 

IGNORE all other RUBBISH!